7x^2-70x-168=0

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Solution for 7x^2-70x-168=0 equation:



7x^2-70x-168=0
a = 7; b = -70; c = -168;
Δ = b2-4ac
Δ = -702-4·7·(-168)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9604}=98$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-98}{2*7}=\frac{-28}{14} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+98}{2*7}=\frac{168}{14} =12 $

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